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Quadratic equations play a vital role in Class X mathematics, forming the foundation for many advanced math topics. We will help you understand the standard form of quadratic equations, how to represent situations mathematically, and techniques for solving these equations using factorization. We’ll also cover how to check if an equation is quadratic, find roots, and understand the nature of roots using the discriminant.
Standard Form of a Quadratic Equation : ax² +bx + c=0
Check Whether the Following are Quadratic Equations
To check if an equation is quadratic, we look for the highest power of the variable, which should be 2. Let’s look at some examples:
Examples of quadratic equations:
2x² - 2x + 3=0, 3x² - 2x =0, x² + 4 =0
Examples of equations which are not quadratic:
x³ - 2x² - 2x+3=0 |
Reason: The highest power on x is 3. |
x² + 2x + x-1 = 0 | Reason: The power on x is -1, not a whole number. |
4x² - 2 | Reason: The variable x is under a radical symbol. |
x² + 2 /x | Reason: The variable x is in the denominator. |
Represent the Following Situations in the Form of Quadratic Equations
EXERCISE 4.1 Q2(i) The area of a rectangular plot is 528 m² . The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.
Steps | Reasoning |
Let breadth = x m Length = 2x+1 m | Assign the variable to the unknown quantity The length is one more than twice its breadth. |
x(2x+1)=528 | Area = Length * breadth = 528 |
2x²+x-528=0 | General form: ax²+bx+c=0 |
Steps | Reasoning |
Let the required numbers are x and x+1 | Assign the variables to the unknown quantity |
x(x+1)=306 | Using: Product is 306 |
x²+x-306=0 | General form: ax²+bx+c=0 |
EXERCISE 4.1 Q2 (iii) Rohan’s mother is 26 years older than him. The product of their ages (in years) 3 years from now will be 360. We would like to find Rohan’s present age.
Steps | Reasoning |
Rohan's age= x years Mother's age = x+26 yrs | Assign the variable to the unknown quantity Rohan’s mother is 26 years older than him. |
(x+3)(x+29)=360 | After 3 years their ages will be x+3 and x+26+3 |
x²+32x-273=0 | General form: ax²+bx+c=0 |
EXERCISE 4.1 Q2 (iv) A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.
Steps | Reasoning |
speed of the train=x km/h | Assign the variable to the unknown quantity |
time=480/x hours | time = distance/speed |
time = 480/(x-8) | Reduced speed = x-8 km/h |
480/(x-8) -480/x =3 | Difference of time is 3 hours |